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用JAVA栈的方法实现十进制转十六进制

看到这道题目想到了三个方法,依次给你列出(栈的方式,递归,数组) 栈的方式: //思路:将十进制数(number)除以R取余,让取得的余数(number Mod R )进栈,让十进制数变为 number/R,重复上述过程,直到number等于0为止,然后依次从栈中取出数据...

public static String baseConverter(int decNumber,int base){ String[] digits = new String[]{"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"}; String result = ""; Stack remStack = new Stack(); while(decNumber > 0)...

import java.util.Scanner; import java.util.Stack; public class TestNumTran { public static void main(String[] args) { Scanner scan = new Scanner(System.in); System.out.println("请输入需要转换的数字:"); int num = scan.nextInt()...

import java.util.Scanner;import java.util.Stack;public class Test {public static void main(String[] args) {System.out.println("请输入十进制数");Scanner sc = new Scanner(System.in);int x = sc.nextInt();System.out.println("请输入...

写的不错,顶

用顺序栈实现数制转换的Java程序如下: import java.util.Scanner;import java.util.Stack;public class jinzhi3 { public static void main(String arg[]){ Scanner y=new Scanner(System.in); System.out.println("请输入十进制数"); int b=y.n...

import java.util.Scanner; import java.util.Stack;/** * 将十进制数转换为八进制数 * * @author austin */ public class DecimalToOctalConvertor { /** * @param args */ public static void main(String[] args) { /* * 接收一个用户从通过...

public class Change { public static void main(String[] args) { System.out.println(binary(100)); System.out.println(octonary(100)); System.out.println(hexadecimal(1000)); } public static String binary(int a){ byte[] b = new byte...

将十进制数转换为八进制数 * * @author austin */ public class DecimalToOctalConvertor { /** * @param args */ public static void main(String[] args) { /*

直接在分割的时候就执行压栈操作,出栈时移位相加,一个栈就能解决,不过毫无意义,在开发中并没有什么卵用。 有问题欢迎提问,满意请采纳,谢谢!

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