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hCl 2.0.1

(1)200mL (2)200mL (1)Zn + 2HCl =" " ZnCl 2 + H 2 ↑ 2 mol 22.4L n(HCl) 4.48Ln(HCl)= 4.48L÷22.4L×2 mol ="0.4" molV(HCl)= n(HCl)÷c(HCl)=" 0.4" mol÷2.0mol·L -1 =" 0.2L" = 200mL(2)Zn + 2HCl =" " ZnCl 2 + H 2 ↑ 73...

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